7 cheese pizzas and 38 pepperoni pizzas were sold.
Step-by-step explanation:
Given,
Cost of one pepperoni pizza = $8.50
Cost of one cheese pizza = $6.00
Total pizzas sold = 45
Total worth = $365
Let,
x be the number of pepperoni pizzas sold.
y be the number of cheese pizzas sold.
According to given statement;
x+y=45 Eqn 1
8.50x+6y=365 Eqn 2
Multiplying Eqn 1 by 6
[tex]6(x+y=45)\\6x+6y=270\ \ \ Eqn\ 3[/tex]
Subtracting Eqn 3 from Eqn 2
[tex](8.50x+6y)-(6x+6y)=365-270\\8.50x+6y-6x-6y=95\\2.50x=95[/tex]
Dividing both sides by 2.50
[tex]\frac{2.50x}{2.50}=\frac{95}{2.50}\\x=38[/tex]
Putting x=38 in Eqn 1
[tex]38+y=45\\y=45-38\\y=7[/tex]
7 cheese pizzas and 38 pepperoni pizzas were sold.
Keywords: linear equation, subtraction
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