how to find a circumference of the circle that circumscribes a triangle with side lenghts 3,4,5

Question

12-06-2016
Mathematics

contestada

how to find a circumference of the circle that circumscribes a triangle with side lenghts 3,4,5

Respuesta :

Otras preguntas

The second letter of the Koeppen letter code gives information about: a. the precipitation characteristics of the climate subtype. b. the primary climate of t

An electric dipole with its center located at the origin of a Cartesian coordinate system oscillates along the x axis, creating an electromagnetic wave. Part A

ABC is the middle line of MN in an equilateral triangle. If AB = 8 cm, then find the perimeter MBN. A)18 cm B)24 cm C)16 cm D)20 cm E)12 cm..

Penny gets an acting job on Friday that she attributes to her good acting. But when she doesn’t get the next acting job, she blames the casting director for not

Which of the following is a difference between internal attributions and external attributions? a. Internal attributions are those in which behavior is thought

Herbicide rollers can be effective for controlling low growing brush in areas where spraying is not possible because of the proximity of sensitive crops. True

Technician A says that liquid cooling an engine helps to maintain a consistent operating temperature. Technician B says that oil is circulated through the cooli

Which of the following acts financially rewards whistle-blowers who expose fraud related to governmental programs and wrongdoing related to consumer financial p

AABC has vertices A(-4, 4), B(-1,2), and C(-4,1). What are the coordinates of B' after a translation of (x,y)--(x+2, y+1), then a reflection across the x-axis?

The existence of subcultures: A) makes corporate life easier B) complicates the development and management of an organizational culture. C) diversifies corporat

Tucon Tucon · Answer 1 · 2016-06-12T07:54:21+02:00

[tex]\displaystyle \\ \texttt{We have } \Delta ABC \texttt{ with: } \\ \\ AB = 3 \\ AC = 4 \\ BC = 5 \\ \\ AB^2 + AC^2 = 3^2+4^2 = 9 + 16 = 25 = BC^2 \\ \Longrightarrow~~ \ \textless \ A = 90^o \\ \Longrightarrow~~ BC = \texttt{hypotenuse} \\ \Longrightarrow~~ \texttt{diameter of the circle: } D = BC = 5 \\ \\ \Longrightarrow~~R = \frac{D}{2} = \frac{5}{2} = 2,5 \\ \\ \Longrightarrow~~\texttt{circumference of the circle: } = 2\pi R = \pi D = \boxed{5\pi}[/tex]