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A gas mixture contains 0.150 mol of oxygen (O2) gas and 0.211 mol of argon (Ar) gas. The total pressure of the mixture is 159 kPa. What is the partial pressure of Ar in the mixture? Report your answer with the correct number of significant figures.

Respuesta :

Answer:

The partial pressure of argon is 92.9 kPa (or 0.917 atm)

Explanation:

Step 1: Data given

Moles of O2 = 0.150 mol

Moles of argon = 0.211 mol

Total pressure = 159 kPa

Step 2: Calculate mole fraction of Ar

Mole fraction Ar = 0.211 / (0.211+0.150)

Mole fraction Ar = 0.584

Step 3: Calculate the partial pressure

Partial pressure of argon =  Mole fraction  * Total pressure

Partial pressure argon = 0.584 * 159 kPa

Partial pressure argon = 92.9 kPa (= 0.917 atm)

The partial pressure of argon is 92.9 kPa (or 0.917 atm)

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