contestada

An airplane is flying in a horizontal circle at a
speed of 100 m/s. The 80.0 kg pilot does not
want the centripetal acceleration to exceed
6.92 times free-fall acceleration.
Find the minimum radius of the plane’s
path. The acceleration due to gravity is 9.81
m/s2
.

Respuesta :

Answer:

the minimum radius of the plane path would be 147.45 meters.

Explanation:

given speed of the plane = 100 m/s.

and centripetal acceleration ≤ 6.92×g

we know that centripetal acceleration = [tex]\frac{v^{2}}{r}[/tex]

therefore[tex]\frac{v^{2}}{r}\leq 6.92\times 9.81\\[/tex]

therefore [tex]r\geq \frac{100\times 100}{6.92\times 9.81}[/tex]

therefore r ≥ 147.54 meters