Answer:
F = 14.83N
Explanation:
According to the given data:
F1 = [0, -8.8]N
F = [Fx,Fy]
F3 = [-6.7*cos(56°),-6.7*sin(56°)]N
The sum of forces on the x-axis, will be:
[tex]Fx +F3_x=0[/tex] => Fx = 6.7*cos(56°)
Fx = 3.75N
The sum of forces on the y-axis, will be:
[tex]Fy +F3_y + F1_y=0[/tex] => Fy = 6.7*sin(56°)+8.8
Fy = 14.35N
The magnitude of F is: F = 14.83N at an angle of 14.65° above the horizontal