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A ball having mass 2 kg is fastened at the end of a flagpole that is connected to the side of a tall building at point P . The length of the flagpole is 4.6 m, and it makes an angle 1.0472 rad (60◦ ) with the horizontal. The acceleration of gravity is 9.8 m/s 2 . If the ball becomes loose and starts to fall, determine the magnitude of its angular momentum after 27 s about P. Neglect air resistance.

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Answer:

1217.6 kg m^{2} / s

Explanation:

mass (m) =  2 kg

length (L) = 4.6 m

angle = 1.0472 rad = 60 degrees

acceleration due to gravity (g) = 9.8 m/s^{2}

time (t) = 27 s

angular momentum = m x g x L x t x cosθ

angular momentum = 2 x 9.8 x 4.6 x 27 x cos 60 = 1217.6 kg m^{2} / s

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