A hotel has 200 rooms. Those with kitchen facilities rent for $300 per night and those without kitchen facilities rent for $180 per night. One night a total of $45,600 was collected. How many of each type of room was rented?

Respuesta :

80 rooms with kitchen facility and 120 rooms without kitchen facility were rented.

Step-by-step explanation:

Given,

Total rooms = 200

Cost of kitchen facility rooms = $300 per night

Cost of without kitchen facility rooms = $180 per night

Total collected = $45600

Let,

x be the number of kitchen facility rooms.

y be the number of without kitchen facility rooms.

According to given statement;

x+y=200   Eqn 1

300x+180y=45600   Eqn 2

From Eqn 1

x=200-y   Eqn 3

Putting value of x from Eqn 3 in Eqn 2

[tex]300(200-y)+180y=45600\\60000-300y+180y=45600\\-120y=45600-60000\\-120y=-14400\\[/tex]

Dividing both sides by -120

[tex]\frac{-120y}{-120}=\frac{-14400}{-120}\\y=120[/tex]

Putting y=120 in Eqn 1

[tex]x+120=200\\x=200-120\\x=80\\[/tex]

80 rooms with kitchen facility and 120 rooms without kitchen facility were rented.

Keywords: linear equations, substitution method

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