Answer:
Mass = 36.38 g
Explanation:
Given data:
Mass of hydrogen = 30.0 g
Mass of nitrogen = 30.0 g
Theoretical yield of reaction = ?
Mass of ammonia = ?
Chemical equation:
N₂+ 3H₂ → 2NH₃
Number of moles of N₂:
Number of moles = Mass /molar mass
Number of moles = 30 g / 28 g/mol
Number of moles = 1.07 mol
Number of moles of H₂:
Number of moles = Mass /molar mass
Number of moles = 30 g / 2g/mol
Number of moles = 15 mol
Now we will compare the moles of NH₃ with hydrogen and nitrogen .
H₂ : NH₃
3 : 2
15 : 2/3×15= 10 mol
N₂ : NH₃
1 : 2
1.07 : 2 × 1.07= 2.14 mol
The number of moles of NH₃ produced by nitrogen are less it will be limiting reactant.
Mass of ammonia:
Mass of NH₃ = moles × molar mass
Mass =2.14 mol × 17 g/mol
Mass = 36.38 g
