Answer:
The volume that this same amount of air will occupy in his lungs when he reaches a depth of 124 m is - 0.27 L.
Explanation:
Using Boyle's law
[tex]{P_1}\times {V_1}={P_2}\times {V_2}[/tex]
Given ,
V₁ = 3.6 L
V₂ = ?
P₁ = 1.0 atm
P₂ = 13.3 atm (From correct source)
Using above equation as:
[tex]{P_1}\times {V_1}={P_2}\times {V_2}[/tex]
[tex]{1.0\ atm}\times {3.6\ L}={13.3\ atm}\times {V_2}[/tex]
[tex]{V_2}=\frac{{1.0}\times {3.6}}{13.3}\ L[/tex]
[tex]{V_2}=0.27\ L[/tex]
The volume that this same amount of air will occupy in his lungs when he reaches a depth of 124 m is - 0.27 L.
