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Write the net ionic equation for the following reaction: Aqueous solutions of copper(II) nitrate and sodium hydroxide are mixed to form solid copper(II) hydroxide and aqueous sodium nitrate. 1. Cu2+ + 2 NO− 3 + 2Na+ + 2OH− → Cu2+ + 2 OH− + 2 Na+ + 2 NO− 3 2. Cu2+ + 2 OH− → Cu(OH)2(s) 3. Cu(NO3)2(aq) + 2 NaOH(aq) → Cu(OH)2(s) + 2 NaNO3(aq) 4. 2 Na+ + 2 NO− 3 → 2 NaNO3(aq)

Respuesta :

IthaloAbreu

Answer:

3. Cu(NO₃)₂(aq) + 2NaOH(aq) → Cu(OH)₂(s) + 2NaNO₃(aq)

Explanation:

Copper(II) is the ion Cu⁺² and nitrate is the ion NO₃⁻, so the compound will be formed by the change of the charge without the signals: Cu(NO₃)₂. Sodium has the ion Na⁺, and hydroxide OH⁻, so the compound is NaOH.

Then, copper (II) hydroxide is Cu(OH)₂, and sodium nitrate is NaNO₃.

The reaction is:

Cu(NO₃)₂(aq) + NaOH(aq) → Cu(OH)₂(s) + NaNO₃(aq)

To balance the equation, the elements must have the same amount at both sides of it, so we must multiply NaOH and NaNO₃ by 2:

Cu(NO₃)₂(aq) + 2NaOH(aq) → Cu(OH)₂(s) + 2NaNO₃(aq)