Answer:
1033 g
Explanation:
The amount of heat energy required to roast the pork = 10*1600 kJ = 16000 kJ.
Using the change in enthalpy of the reaction given in the question and the balanced chemical equation:
3 moles of carbon dioxide is equivalent to -2044 kJ. 1 mole of carbon dioxide is equivalent to 44 g. Thus:
The mass of carbon dioxide emitted is:
[tex]m_{CO_{2} } = 16000 kJ*\frac{3 mol }{2044 kJ}*\frac{44 g}{1 mol} = 1033 g[/tex]