Respuesta :
Answer:
Electric force, [tex]F=-3.59\times 10^6\ N[/tex]
Explanation:
Given that,
Electric charge 1, [tex]q_1=+40\ C[/tex]
Electric charge 2, [tex]q_2=-40\ C[/tex]
Distance, [tex]d=2\ km=2\times 10^3\ m[/tex]
To find,
The electric force between these two sets of charges.
Solution,
There exists a force between two electric charges and this force is called electrostatic force. It is equal to the product of electric charged divided by square of distance between them.
[tex]F=k\dfrac{q_1q_2}{d^2}[/tex]
k is the electrostatic constant
[tex]F=8.99\times 10^9\times \dfrac{40\times (-40)}{(2\times 10^3)^2}[/tex]
[tex]F=-3.59\times 10^6\ N[/tex]
So, the electric force between these two sets of charges is [tex]-3.59\times 10^6\ N[/tex].
The electric force between the sets of two charges in the thundercloud with the given parameters is; F = -3.596 * 10⁶ N
What is the electric force between the charges?
The formula for electric force between two charges is;
F = Kq₁*q₂/r²
where;
k is coulombs constant = 8.99 * 10⁹ N.m²/c²
q₁ is charge 1
q₂ is charge 2
r is distance of separation of charges
We are given;
q₁ = +40 C
q₂ = -40 C
r = 2.0 km = 2000 m
Thus force is;
F = 8.99 * 10⁹ * 40 * (-40)/2000²
F = -3.596 * 10⁶ N
Read more about Electric Force between charges at; https://brainly.com/question/17692887
