The length of a rectangle is increasing at a rate of 8 centimeters per second and its width is increasing at a rate of 3 centimeters per second. When the length is 20 cm and the width is 10 cm, how fast is the area of the rectangle increasing?

Respuesta :

Area of rectangle is increasing at 140 cm²/s when the length is 20 cm and the width is 10 cm.

Step-by-step explanation:

Area = Length x Width

A = LW

Differentiating with respect to time

            [tex]\frac{dA}{dt}=L\frac{dW}{dt}+W\frac{dL}{dt}[/tex]

Length, L = 20 cm

Width, W = 10 cm

[tex]\frac{dW}{dt}=3cm/s\\\\\frac{dL}{dt}=8cm/s[/tex]

Substituting

           [tex]\frac{dA}{dt}=20\times 3+10\times 8\\\\\frac{dA}{dt}=60+80\\\\\frac{dA}{dt}=140cm^2/s[/tex]

Area of rectangle is increasing at 140 cm²/s when the length is 20 cm and the width is 10 cm.