Answer:
Option (B) is correct.
Explanation:
Given that,
D1 = 1.46
D2 = 1.46
D3 = 15.25
[tex]Stock\ value=\frac{D1}{(1+r)^{t}}+\frac{D2}{(1+r)^{t}}+\frac{D3}{(1+r)^{t}}[/tex]
[tex]Stock\ value=\frac{1.46}{(1.185)^{1}}+\frac{1.46}{(1.185)^{2}}+\frac{15.25}{(1.185)^{3}}[/tex]
= 1.2320 + 1.0397 + 9.1646
= 11.44