Answer:
Nancy Spent [tex]1\frac{8}{12}[/tex] hours more than Sally.
Step-by-step explanation:
Given:
Nancy spent 3 2/6 hours working on her homework.
Hours spent on Homework by Nancy = [tex]3\frac{2}{6}[/tex]
[tex]3\frac{2}{6}[/tex] can be Rewritten as [tex]\frac{20}{6}[/tex]
Hours spent on Homework by Nancy = [tex]\frac{20}{6}[/tex]
Also Given;
Sally spent 1 8/12 hours working on her homework.
Hours spent on Homework by Sally = [tex]1\frac{8}{12}[/tex]
[tex]1\frac{8}{12}[/tex] can be Rewritten as [tex]\frac{20}{12}[/tex]
Hours spent on Homework by Sally = [tex]\frac{20}{12}[/tex]
We need to find Hours spent more by Nancy;
It can be calculated by subtracting Hours spent by Sally with Hours spent by Nancy;
Hours Spent More = [tex]\frac{20}{6}-\frac{20}{12}[/tex]
Now we will make the denominators common then solve for the same.
Hours Spent More =[tex]\frac{20\times 2}{6\times2}-\frac{20\times1}{12\times1}= \frac{40}{12}-\frac{20}{12}= \frac{40-20}{12}= \frac{20}{12} \ hrs[/tex]
Hence [tex]\frac{20}{12} \ hrs[/tex] can be rewritten as [tex]1\frac{8}{12}[/tex].
Hence Nancy Spent [tex]1\frac{8}{12}[/tex] hours more than Sally.