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Light of wavelength 687 nm is incident on a single slit 0.75 mm wide. At what distance from the slit should a screen be placed if the second dark fringe in the diffraction pattern is to be 1.7 mm from the center of the diffraction pattern? A) 0.39 m
B) 0.47 m
C) 0.93 m
D) 1.1 m
E) 1.9 m

Respuesta :

Answer:

D = 0.93 m

Explanation:

given,

wavelength of the light source (λ)= 687 nm

slits is separated (d) = 0.75 mm

distance to form interference pattern(D) =?

n = 2

now, using displacement formula

 [tex]y = \dfrac{n\lambda\ D}{d}[/tex]

where y is the fringe width

y = 1.7 mm

 [tex]1.7 = \dfrac{2\times 687\times 10^{-6}\times D}{0.75}[/tex]

 [tex]D = \dfrac{1.7 \times 0.75}{2\times 687\times 10^{-6}}[/tex]

     D = 927.95 mm

     D = 0.927 m

     D = 0.93 m

Hence, the correct answer is option C

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