A pendulum is constructed from a 5.9 kg mass attached to a strong cord of length 1.6 m also attached to a ceiling. Originally hanging vertically, the mass is pulled aside a small distance of 7.1 cm and released from rest. While the mass is swinging the cord exerts an almost-constant force on it. For this problem, assume the force is constant as the mass swings. How much work in J does the cord do to the mass as the mass swings a distance of 8.0 cm?

Respuesta :

Answer:

Work done is zero

Solution:

As per the question:

Mass of the pendulum, m = 5.9 kg

Length of the cord, l = 1.6 m

Distance moved by the mass, x = 7.1 cm = 0.071 m

Now,

To calculate the work done when the displacement of the mass is 8 cm:

Work done is given by the formula:

W = [tex]\vec{F}.\vec{x} = Fxcos\theta[/tex]

Also, we know that in simple pendulum, the force due to the string reamins perpendicular to the displacement of the mass from the mean position.

Thus

[tex]\theta = 90^{\circ}[/tex]

[tex]W = F.xcos90^{\circ} = 0\ J[/tex]

Therefore, the work done is zero.