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During a tug-of-war, team A pulls on team B by applying a force of 1550 N to the rope between them. The rope remains parallel to the ground. How much work does team A do if they pull team B toward them a distance of 2.3 m

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Answer:

3565 J

Explanation:

F = Force applied = 1550 N

s = Displacement caused by the applied force = 2.3 m

[tex]\theta[/tex] = Angle at which the force is applied = 0°

When we multiply force, displacement and the angle at which the force is applied we get work

Work done is given by

[tex]W=Fscos\theta\\\Rightarrow W=1550\times 2.3\times cos 0\\\Rightarrow W=3565\ J[/tex]

The work done by team A is 3565 J

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