Answer:
[tex]-96.465m[/tex] joule
Explanation:
Let m = mass of the car and v1 = initial velocity and v2 = final velocity
Given.
Initial velocity = 100 km/h
final velocity = 50 km/h
What is work done in the car to slow it from 100km/h to 50km/h?
[tex]v1=100km/h=27.78m/s[/tex]
[tex]v2=50km/h=13.89m/s[/tex]
The work done in the car to slow it from v1 to v2.
w=Δk
[tex]w=k2-k1[/tex]
[tex]w= \frac{1}{2}m(v2)^{2}- \frac{1}{2}m(v1)^{2}[/tex]
[tex]w=\frac{1}{2} m(v2-v1)^{2}[/tex]
[tex]w=\frac{1}{2}\times m(13.89 -27.78)^{2}[/tex]
[tex]w=\frac{1}{2}\times m(-13.89)^{2}[/tex]
[tex]w=\frac{1}{2}\times m\times (-192.93)[/tex]
[tex]w=-96.465m[/tex] joule.
Therefore, the work done is [tex]-96.465m[/tex] joule
