Answer: temperature of the hot reservoir is 303.52K
Explanation:
Th=temperagture of hot reservoir
Tc=temperature of cold reservoir 263K
Eff=efficiency of the refrigerator
Cop=coefficient of performance
7
Eff=1/cop
Eff=1/7
Eff=0.142
Eff=1-263/th
0.142-1=-263/th
-0.858=-263/th
Th=303.52K
Answer:
The hot reservoir temperature for the refrigerator is [tex]30.37[/tex]°[tex]C[/tex].
Explanation:
Given:
Cold temperature [tex]= -10.0[/tex]°[tex]C[/tex].
Coefficient of performance = [tex]7. 00[/tex]
Step 1:
[tex]TH =[/tex] Temperature of hot reservoir
[tex]TC =[/tex] Temperature of cold reservoir [tex]263K[/tex] (in Kelvin)
[tex]E =[/tex] Efficiency of the refrigerator
[tex]C =[/tex]Coefficient of performance [tex]= 7. 00[/tex]
From the formula,
[tex]E=1/C[/tex]
Step 2:
Substitute the values,
[tex]E=1/7[/tex]
[tex]E=0.142[/tex]
[tex]E=1-263/TH[/tex]
[tex]0.142-1=-263/TH[/tex]
[tex]-0.858=-263/TH[/tex]
[tex]TH=303.52K[/tex]
Step 3:
Convert into celsius,
[tex]TH=30.37[/tex]°[tex]C[/tex]
Therefore, the hot reservoir temperature for the refrigerator is [tex]30.37[/tex]°[tex]C[/tex].
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