Answer:
390.34 g of glucose will be produced if 13 moles of carbon dioxide react.
Explanation:
Moles of carbon dioxide = 13 moles
According to the reaction shown below:-
[tex]6 CO_2_{(g)} + 6 H_2O_{(l)}\rightarrow C_6H_{12}O_6_{(aq)} + 6 O_2_{(g)}[/tex]
6 moles of carbon dioxide are required to produce 1 mole of glucose
Also,
1 mole of carbon dioxide is required to produce [tex]\frac{1}{6}[/tex] mole of glucose.
So,
13 moles of carbon dioxide are required to produce [tex]\frac{1}{6}\times 13[/tex] mole of glucose.
Moles of glucose produced = 2.1667 moles
Molar mass of glucose = 180.156 g/mol
The formula for the calculation of moles is shown below:
[tex]moles = \frac{Mass\ taken}{Molar\ mass}[/tex]
Thus,
[tex]2.1667\ mole= \frac{Mass}{180.156\ g/mol}[/tex]
[tex]Mass_{glucose}= 390.34\ g[/tex]
390.34 g of glucose will be produced if 13 moles of carbon dioxide react.
