Respuesta :

Answer:

[tex]a_6_3=371[/tex]

Step-by-step explanation:

we know that

In an Arithmetic Sequence the difference between one term and the next is a constant and this constant is called the common difference

we have

[tex]-1,5,11,...[/tex]

Let

[tex]a_1=-1\\a_2=5\\a_3=11[/tex]

[tex]a_2-a_1=5-(-1)=5+1=6[/tex]

[tex]a_3-a_2=11-5=6[/tex]

The common difference is [tex]d=6[/tex]

We can write an Arithmetic Sequence as a rule

[tex]a_n=a_1+d(n-1)[/tex]

where

a_n is the nth term                

d is the common difference

a_1 is the first term

n is the number of terms

Find the 63rd term of the arithmetic sequence

we have

[tex]n=63\\d=6\\a_1=-1[/tex]

substitute

[tex]a_6_3=-1+6(63-1)[/tex]

[tex]a_6_3=-1+6(62)[/tex]

[tex]a_6_3=-1+372[/tex]

[tex]a_6_3=371[/tex]