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In the sequence 1, 2, 4, 8, 16, 32, . . . , each term after the first is twice the previous term. What is the sum of the 16th, 17th, and 18th terms in the sequence? 218 3(217) 7(216) 3(216) 7(215) Next Previous HelpEnd Review Review Screen

Respuesta :

MechEngineer

Answer:

229376

Step-by-step explanation:

So we can model the sequence of 1,2,4,8,16,32,... as [tex] 2^{n-1}[/tex] where n = 1,2,3,...

n = 16th, 17th, 18th then the terms are

[tex]2^{15} = 32768[/tex]

[tex]2^{16} = 65536[/tex]

[tex]2^{17} = 131072[/tex]

So the sum of the 3 terms is 32768 + 65536 + 131072 = 229376

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