Answer:
Kp = 7.85x10^-5
Explanation:
To do this, let's write again the given equation:
X + 3Y <------> 2Z Kc = 0.0504
We know that the expression for Kc would be:
Kc = [Z]² / [X] * [Y]³
And the expression for pressure is:
P = nRT/V
The expression of n/V is concentration so
P = CRT
To calculate the value of Kp, is the same for Kc but instead of using concentrations, we use the pressure:
Kp = pZ² / pX * pY³
After we replace the values of p into the above equation, we have the following:
Kp = ([Z]RT)² / ([X]RT) * ([Y]RT)³
Kp = [Z]²(RT)² / [X]RT * [Y]³(RT)³ --->Here we take common factor of RT so
Kp = [Z]² / [X] * [Y]³ * (RT)^(2 - (1 + 3))
The part in bolding is the value of Kc so:
Kp = Kc * (RT)^-2
Replacing the values now of Kc, R (0.082 L atm/ K mol) and T, let's calculate Kp:
Kp = 0.0504 * (0.082 * 309)^-2
Kp = 7.85x10^-5
