The inductive reactance of the circuit is exactly twice the resistance: XL=2R. Adjust the phasor that represents the voltage across the inductor (VL) at the instant indicated to the proper length and orientation.

Respuesta :

Answer:

∅=[tex]63.43^{0}[/tex]

Explanation:

z=impedance

[tex]x_{l}[/tex]=2R

R=R

The resultant of the resistances in the circuit is called impedance

[tex]x_{l}[/tex] is inductive reactance of the circuit

R is the resistance of the resistor

z=[tex]\sqrt{xl^{2}+R^2 }[/tex]

z=[tex]\sqrt{2R^{2}+R^2 }[/tex]

Z=[tex]\sqrt{5R^2}[/tex]

Z=R[tex]\sqrt{5}[/tex]ohms

tan∅=2R/R

tan∅=2

∅=Tan^-1(2)

∅=[tex]63.43^{0}[/tex]

phase angle is ∅=[tex]63.43^{0}[/tex]

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