Suppose a ball of putty moving horizontally with 1 kg·m/s of momentum collides with and sticks to an identical ball of putty moving vertically with 1 kg·m/s of momentum. What is the magnitude of their combined momentum?

Respuesta :

Answer:

[tex]P=\sqrt{2}\ kg.m/s[/tex]

Explanation:

Given that

For the first ball ,linear momentum P₁ = 1 kg.m/s (Horizontal)

For the second ball ,linear momentum P₂ = 1 kg.m/s ( vertically)

Lets take balls are moving in the x-y plane

As we know that linear momentum is a vector quantity

P₁ = 1  i kg.m/s

P₂ = 1 j kg.m/s

There combine linear momentum

P= P₁ + P₂

P = 1  i  + 1 j kg.m/s

The magnitude of the linear momentum P

[tex]P=\sqrt{1^2+1^2}\ kg.m/s[/tex]

[tex]P=\sqrt{2}\ kg.m/s[/tex]

Answer:

The magnitude of their combined momentum would be 1.41 kg m/s

Explanation:

I'm not sure why that is just the correct answer. Sorry.