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The sum of three numbers is 45. The second of the three numbers is three more than twice the first number, x. The third number is two more than the first number, x. Which equation can be used to solve for the first number, x?

a. x+x+x=45

b. x+(x+3)+(x+2)=131

c. x(2x+3)+(x+2)=45

d. x+(2x+3)+x=45

Respuesta :

ssdsdancediva
the answer is C. x(2x+3)+(x+2)=45
eternal3fear
let's say that the first number is x
the second is y
and the third is z

we start off with the equation that the sum of the three number is 45
[tex] x + y + z = 45 [/tex]

the "second of the three numbers is three more than twice the first number" means that
[tex] y = 2x + 3 [/tex]

the "third number is two more than the first number" means that
[tex] z = x + 2 [/tex]

we plug [tex]y[/tex] and [tex]z[/tex] back into the first first equation and get
[tex] x + (2x+3) + (x+2)=45 [/tex]

assuming you are missing an addition sign in your option C
your answer would be C. x+(2x+3)+(x+2)=45

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