Respuesta :

nkirotedoreen46

Answer:

0.048 g

Explanation:

We are given;

  • Moles of hydrogen gas as 1.98 × 10^-3 moles

We are required to calculate the mass of Magnesium that reacted

  • Assuming the equation for the reaction is;

Mg + 2HCl → MgCl₂ + H₂

  • From the reaction;

1 mole of magnesium reacts with 2 moles of HCl to produce 1 mole of MgCl₂ and 1 mole of hydrogen gas

  • Therefore;

Mole ratio of Mg : H₂ is 1 : 1

Thus, moles of Mg = Moles of H₂

Moles of Mg is 1.98 × 10^-3 moles

But, molar mass of Mg = 24.305 g/mol

Therefore;

Mass of Mg = 1.98 × 10^-3 moles × 24.305 g/mol

                  = 0.048 g

The mass of Mg that reacted is 0.048 g

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