The capacitance of the system is [tex]1.9\cdot 10^{-11}F[/tex]
Explanation:
The capacitance of a capacitor is given by the following equation:
[tex]C=\frac{Q}{V}[/tex]
where
C is the capacitance
Q is the charge stored in the capacitor
V is the potential difference across the capacitor
In this problem, we have:
[tex]Q=9.4\cdot 10^{-10}C[/tex] is the charge stored
[tex]V=50.0 V[/tex] is the potential difference across it
Substituting into the equation, we find the capacitance:
[tex]C=\frac{9.4\cdot 10^{-10}}{50.0}=1.9\cdot 10^{-11}F[/tex]
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