For this case we have the following system of equations:
[tex]x = 2-2y\\-1 = -2x-3y[/tex]
We substitute the first equation in the second equation:
[tex]-1 = -2 (2-2y) -3y\\-1 = -4 + 4y-3y\\-1 = -4 + y\\-1 + 4 = y\\y = 3[/tex]
Now, we look for the value of the variable "x":
[tex]x = 2-2 (3)\\x = 2-6\\x = -4[/tex]
Thus, the solution of the system is given by:
[tex](x, y): (- 4,3)[/tex]
Answer:
[tex](x, y): (- 4,3)[/tex]
