Respuesta :
Answer:
The balanced single displacement reaction between aluminum and copper sulphate is as follows.
[tex]2Al(s)+3CuSO_{4}(aq)\rightarrow Al_{2}(SO_{4})_{3}(aq)+3Cu(s)[/tex]
Explanation:
The given ions are as follows.
[tex]Al^{3+}[/tex]- Aluminium ion and copper sulfate ion.
Single displacement reaction occurs one element replaces another element.
Hence, the balanced chemical reaction is as follows.
[tex]2Al(s)+3CuSO_{4}(aq)\rightarrow Al_{2}(SO_{4})_{3}(aq)+3Cu(s)[/tex]
Oxidation half reaction:
[tex]Al\rightarrow Al^{3+}+3e^{-}[/tex]
Aluminium loses three electrons.
Reduction half reaction:
[tex]Cu^{2+}+2e^{-}\rightarrow Cu(s)[/tex]
Copper gain three electrons.
Answer:
2Al + 3Cu(SO4) --> 3Cu + Al2(SO4)3
Explanation:
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