Answer:
54 square feet
Step-by-step explanation:
The width of the rectangle ABCD is 8 feet and the area of the same rectangle is 96 square feet.
Hence, the length of the rectangle is (96 ÷ 8) = 12 feet.
Now, if the rectangle ABCD is dilated to rectangle A'B'C'D', then the length and the width of the new rectangle will be changed in the same ratio.
So, [tex]\frac{AB}{A'B'} = \frac{BC}{B'C'}[/tex] {Where AB is the length and BC is the width}
⇒ [tex]\frac{12}{A'B'} = \frac{8}{6}[/tex]
⇒ A'B' = 9 feet
Therefore, the area of the dilated rectangle A'B'C'D' will be A'B' × B'C' = 9 × 6 = 54 square feet. (Answer)
