Answer:
0.092 M
Explanation:
Let's consider the following redox reaction.
8 H⁺ + MnO₄⁻ + 5 Fe²⁺ → 5 Fe³⁺ + Mn²⁺ + 4 H₂O
The moles of MnO₄⁻ is:
[tex]36.43 \times 10^{-3} L.\frac{0.025mol}{L} =9.1 \times 10^{-4}mol[/tex]
The molar ratio of MnO₄⁻ to Fe²⁺ is 1:5. Then, the moles of Fe²⁺ are:
5 × (9.1 × 10⁻⁴ mol) = 4.6 × 10⁻³ mol
The concentration of Fe²⁺ is:
[tex]\frac{4.6 \times 10^{-3}mol}{50.00 \times 10^{-3} L} =0.092 M[/tex]
