Answer:
Acceleration, [tex]a=97.67\ m/s^2[/tex]
Explanation:
Given that,
Speed of pilot, v = 475 m/s
Radius of the circle, r = 2310 m
If the pilot is moving in a circular path, it will experience a centripetal acceleration. It is given by the formula as :
[tex]a=\dfrac{v^2}{r}[/tex]
[tex]a=\dfrac{(475\ m/s)^2}{2310\ m}[/tex]
[tex]a=97.67\ m/s^2[/tex]
So, the acceleration experienced by a pilot flying in a circle is [tex]97.67\ m/s^2[/tex]. Hence, this is the required solution.