Answer:
Common difference of the sequence is -7.
Step-by-step explanation:
Given:
First term a = 5
Tenth term [tex]T_{10}[/tex] = -58
we need to find the common difference d.
Now let the number of terms will be 10 since tenth term is given;
Hence n =10
Now Using Arithmetic Progression formula we get;
[tex]T_n = a+(n-1)d[/tex]
Now Substituting the given values in the formula we get;
[tex]T_{10}=5+(10-1)d\\-58 = 5+9d\\-58-5=9d\\-63=9d\\\\-\frac{63}{9}=d\\\\d=-7[/tex]
Hence Common difference of the sequence will be -7.
