Answer:
h. 36
Step-by-step explanation:
For a 68.26% confidence, z = 1.0.
Standard deviation (s) = 30 minutes
The sample size needed to assure that the sample mean does not differ from the true mean by more than 5 minutes is given by:
[tex]5\geq z*\frac{s}{\sqrt n}\\\sqrt n\geq 1*\frac{30}{5}\\n\geq 36[/tex]
The sample size needed is 36.