Answer:
The difference in the sample proportions is not statistically significant at 0.05 significance level.
Step-by-step explanation:
Significance level is missing, it is α=0.05
Let p(public) be the proportion of alumni of the public university who attended at least one class reunion
p(private) be the proportion of alumni of the private university who attended at least one class reunion
Hypotheses are:
[tex]H_{0}[/tex]: p(public) = p(private)
[tex]H_{a}[/tex]: p(public) ≠ p(private)
The formula for the test statistic is given as:
z=[tex]\frac{p1-p2}{\sqrt{{p*(1-p)*(\frac{1}{n1} +\frac{1}{n2}) }}}[/tex] where
Then z=[tex]\frac{0.616-0.623}{\sqrt{{0.619*0.381*(\frac{1}{1311} +\frac{1}{1038}) }}}[/tex] =-0.207
Since p-value of the test statistic is 0.836>0.05 we fail to reject the null hypothesis.