Answer:
The correct answer is option E.
Explanation:
ΔG° = ΔH° - TΔS° (Gibbs's equation)
where :
ΔG° = Gibbs free energy of reaction at temperature T.
ΔH° = Enthalpy of reaction at temperature T.
ΔS° = Entropy change of the reaction
for, endothermic ,ΔH° = positive
And for reaction to spontaneous ΔG° shluld negative,ΔG° = negative
ΔG°(negative)=ΔH°(positive) - T(High)ΔS°
So, for the reaction which are endothermic are spontaneous at high temperatures.
[tex]2Cu(s) + CO_2(g)\rightarrow 2CuO(s) + C(s)[/tex]
The given reaction is endothermic reaction.So, this reaction will be spontaneity at higher temperature