Answer:
[tex]h=2.87\times 10^6\ m[/tex]
Explanation:
Given that,
Initial speed of the spaceship, u = 7.51 km/s = 7510 m/s
At maximum height, final speed of the spaceship, v = 0
Let h is the maximum height reached by the spaceship. Using third equation of motion to find it as :
[tex]v^2-u^2=2gh[/tex]
[tex]u^2=2gh[/tex]
[tex]h=\dfrac{u^2}{2g}[/tex]
[tex]h=\dfrac{(7510)^2}{2\times 9.81}[/tex]
[tex]h=2.87\times 10^6\ m[/tex]
So, the maximum height reached by the spaceship is [tex]2.87\times 10^6\ m[/tex]. Hence, this is the required solution.
