Answer:
0.49 m
0.3675 m
Explanation:
f = Frequency
L = Length
The fundamental length is given by
[tex]L=\frac{\lambda}{2}\\\Rightarrow L=\frac{v}{2f}\\\Rightarrow L=\frac{343}{2\times 350}\\\Rightarrow L=0.49\ m[/tex]
The second harmonic is has [tex]L_a=\lambda=0.49\ m[/tex]
The length of pipe A is 0.49 m
Frequency is given by
[tex]f=\frac{v}{L}\\\Rightarrow f=\frac{343}{0.49}\\\Rightarrow f=700\ Hz[/tex]
For third harmonic n = 3
[tex]v=\lambda f\\\Rightarrow v=\frac{4}{3}L_bf\\\Rightarrow L_b=\frac{3v}{4f}\\\Rightarrow L_b=\frac{3\times 343}{4\times 700}\\\Rightarrow L_b=0.3675\ m[/tex]
The length of pipe B is 0.3675 m
