Answer:
1817.67 J
Explanation:
mass, m = 17.4 kg
Applied force, F = 173 N
θ = 31.5°
distance, s = 13.4 m
μ = 0.148
g = 9.8 m/s^2
According to the diagram
Let N be the normal reaction and f be the friction force.
Net force in vertical direction is zero. So, N + F Sinθ = mg
N = mg - F Sinθ
N = 17.4 x 9.8 - 173 x Sin 31.5°
N = 170.52 - 90.4
N = 80.12 N
Friction force, f = μ N = 0.148 x 80.12 = 11.86 N
net force, Fnet = F cos θ - f
F net = 173 Cos 31.5 - 11.86
F net = 135.65 N
Work don by net force
W = F net x distance
W = 135.65 x 13.4
W = 1817.67 J
Thus, the work done by the net force is 1817.67 J.
