Explanation:
It is given that,
Frequency of vibration, f = 215 Hz
Amplitude, A = 0.832 mm
(a) Let T is the period of this motion. It is given by the following relation as :
[tex]T=\dfrac{1}{f}[/tex]
[tex]T=\dfrac{1}{215}[/tex]
[tex]T=4.65\times 10^{-3}\ s[/tex]
(b) Speed of sound in air, v = 343 m/s
It can be given by :
[tex]v=f\times \lambda[/tex]
[tex]\lambda=\dfrac{v}{f}[/tex]
[tex]\lambda=\dfrac{343\ m/s}{215\ Hz}[/tex]
[tex]\lambda=1.59\ m[/tex]
Hence, this is the required solution.
