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A Carnot heat engine uses a hot reservoir consisting of a large amount of boiling water and a cold reservoir consisting of a large tub of ice and water. In 5 minutes of operation of the engine, the heat rejected by the engine melts a mass of ice equal to 4.35×10−2 kg . Throughout this problem use Lf=3.34×105J/kg for the heat of fusion for water.

Respuesta :

Answer:

Explanation:

Given

In 5 minute [tex]m=4.35\times 10^{-2} kg[/tex] of ice is melted

Latent heat of Fusion [tex]L=3.34\times 10^5 J/kg[/tex]

[tex]T_1=273 K,T_2=373 K[/tex]

Heat Rejected [tex]Q_r=m\times L=4.35\times 10^{-2}\times 3.34\times 10^5[/tex]

[tex]Q_r=14.529\times 3 J[/tex]

[tex]\eta _{carnot}=1-\frac{Q_r}{Q_s}=1-\frac{T_1}{T_2}[/tex]

[tex]\frac{Q_r}{Q_s}=\frac{T_1}{T_2}[/tex]

[tex]Q_s=Q_r\times \frac{T_2}{T_1}[/tex]

[tex]Q_s=14.529\times \frac{373}{273}[/tex]

[tex]Q_s=19.85 kJ[/tex]

[tex]Work\ done=Q_s-Q_r[/tex]

[tex]W=5.32\ kJ[/tex]

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