Respuesta :
Answer:
The height of the image is, h' = 6.0 cm
The image is erect.
Explanation:
Given data,
The object distance, u = -5 cm
The focal length of convex lens, f = 10 cm
The object height, h = 3 cm
The lens formula,
[tex]\frac{1}{f}=\frac{1}{v}-\frac{1}{u}[/tex]
[tex]\frac{1}{10}=\frac{1}{v}-\frac{1}{-5}[/tex]
[tex]\frac{1}{v}=\frac{1}{10}-\frac{1}{5}[/tex]
v = -10 cm
The magnification factor of lens
[tex]m=\frac{-10}{-5}[/tex]
m = 2
[tex]m=\frac{h'}{h}[/tex]
[tex]h'=h\times m[/tex]
[tex]h'=3\times 2[/tex]
h' = 6 cm
The height of the image is, h' = 6 cm
The image is erect.
Answer:
Hi = -6.0 cm
What is the orientation of the image? inverted
