Answer:
[tex]x=19^o[/tex]
[tex]y=131^o[/tex]
Step-by-step explanation:
For this problem i assume that the two lines that look parallel, are parallel
step 1
Find the value of x
we know that
[tex]55^o+(4x)^o=(7x-2)^o[/tex] ----> by corresponding angles
solve for x
[tex]7x-4x=55+2[/tex]
[tex]3x=57[/tex]
[tex]x=19^o[/tex]
step 2
Find the value of y
we know that
[tex]y=55^o+(4x)^o[/tex] ---> by vertical angles
substitute the value of x
[tex]y=55^o+(4*19)^o[/tex]
[tex]y=131^o[/tex]
Alternative method
[tex]y=55^o+(4x)^o[/tex] ---> by vertical angles
[tex]y=(7x-2)^o[/tex] ---> by alternate exterior angles
Solve the system of equations
