Answer:
The integers are 2,3,4
Step-by-step explanation:
Let one integer be = [tex]x[/tex]
Since, the integers are consecutive, so they will increase by one.
So, 2nd integer will be =[tex]x+1[/tex]
3rd integer will be =[tex]x+1+1=x+2[/tex]
It is given that the 3 integers add up to 9.
So, we have the sum equation as:
[tex]x+x+1+x+2=9[/tex]
Solving for [tex]x[/tex]
Combining like terms.
[tex]3x+3=9[/tex]
Subtracting both sides by 3.
[tex]3x+3-3=9-3[/tex]
[tex]3x=6[/tex]
Dividing both sides by 3.
[tex]\frac{3x}{3}=\frac{6}{3}[/tex]
[tex]x=2[/tex]
∴ 1st integer = [tex]2[/tex]
2nd integer = [tex]2+1 = 3[/tex]
3rd integer = [tex]2+2 = 4[/tex]
