The area of square is [tex]x^{2}+10 x+25[/tex] square units
Given that square has side length (x+5) units
To find: area of square
The area of square is given as:
[tex]\text {Area of square }=\mathrm{a}^{2}[/tex]
Where "a" is the length of side
From question, length of each side "a" = x + 5 units
Substituting the value in above formula,
[tex]\text {Area of square }=(x+5)^{2}[/tex]
[tex]{\text {Expanding }(x+5)^{2} \text { using the algebraic identity: }} \\\\ {(a+b)^{2}=a^{2}+2 a b+b^{2}}\end{array}[/tex]
[tex]\begin{array}{l}{\text {Area of square }=x^{2}+2(x)(5)+5^{2}} \\\\ {\text {Area of square }=x^{2}+10 x+25}\end{array}[/tex]
Thus the area of square is [tex]x^{2}+10 x+25[/tex] square units
