Answer:
The gas occupies 43.8 L at a temperature of 219.8 °C
Explanation:
Step 1: Data given
Volume of the gas = 23.55L
Temperature = 118.2 °C
New volume = 43.8 L
Step 2: Calculate changed temperature
(P1*V1)/T1 = (P2*V2)/T2
Let's assume the pressure stays constant, then we have:
V1/T1 = V2/T2
⇒ with V1 = the initial volume = 23.55L
⇒ with T1 = the initial temperature = 118.2 °C
⇒ with V2 = the changed volume = 43.8 L
⇒ with T2 = the changed temperature = TO BE DETERMINED
23.55L/118.2°C = 43.8 L / T2
T2 = 219.8 °C
The gas occupies 43.8 L at a temperature of 219.8 °C
