Answer:
Therefore the value of k = 6.
Step-by-step explanation:
Given:
LN = m
NM = l
OM = k
NO = 4
LO = 8
LM = 8 + k and
Δ LNM ,Δ LON and Δ MON are right Triangle.
To Find :
Om = k = ?
Solution:
In Right angle Triangle By Pythagoras Theorem we have,
[tex](\textrm{Hypotenuse})^{2} = (\textrm{Shorter leg})^{2}+(\textrm{Longer leg})^{2}[/tex]
So, In Right angle Triangle Δ LON we have,
LN² = ON² + OL²
m² = 4² + 8²
m² = 80 ............( 1 )
Now in Right angle Triangle Δ MON we have,
MN² = ON² + MO²
l² = 4² + k² ....................( 2 )
Now In Right angle Triangle Δ LNM we have,
LM² = LN² + MN²
(8 + k)² = m² + l² .................( 3 )
Substituting equation 1 and equation 2 in equation 3
(8+k)² = 80 + 4² + k²
Applying (A+B)² = A² +2AB + B² we get
[tex]64 + 16k+k^{2} = 80+ 16 +k^{2} \\\\16k=96\\\\\therefore k=\frac{96}{16} \\\\\therefore k=6[/tex]
Therefore the value of k = 6.
