Andy, Barry, and Craig are all in a pie-eating contest. Andy ate 4/7 of his pie, Barry ate 7/12 of his pie, and Craig ate 5/8 of his pie. Afterward, their dog Fido ate all the remaining pie. How many more pies did Fido eat than the winner? Express your answer as a fraction or mixed number in simplest form.

Respuesta :

Answer:

[tex](1)(\frac{142}{168})[/tex] is the excess eaten by Fido.

Step-by-step explanation:

The eaten pie ratios are as follows, Andy ate 4/7 of his pie, Barry ate 7/12 of his pie, and Craig ate 5/8 of his pie.

The winner of the contest is Craig, who ate ([tex]\frac{5}{8}[/tex]) of his pie, which is 62.5 %.

The remaining parts of pie are given by,

= [tex](1-\frac{4}{7})+(1-\frac{7}{12})+(1-\frac{5}{8})[/tex]

=[tex]\frac{3}{7} + \frac{5}{12} + \frac{3}{8}[/tex]

= [tex]\frac{205}{168}[/tex]

This  was the amount eaten by dog Fido.

The excess eaten by Fido than winner is,

=[tex]\frac{205}{168} - \frac{5}{8}[/tex]

=[tex]\frac{310}{168}[/tex]

=[tex](1)(\frac{142}{168})[/tex]